X^2+8(m+2)+7m+3=0

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Solution for X^2+8(m+2)+7m+3=0 equation:



X^2+8(X+2)+7X+3=0
We add all the numbers together, and all the variables
X^2+7X+8(X+2)+3=0
We multiply parentheses
X^2+7X+8X+16+3=0
We add all the numbers together, and all the variables
X^2+15X+19=0
a = 1; b = 15; c = +19;
Δ = b2-4ac
Δ = 152-4·1·19
Δ = 149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{149}}{2*1}=\frac{-15-\sqrt{149}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{149}}{2*1}=\frac{-15+\sqrt{149}}{2} $

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